Consider the equilibrium system described by the chemical reaction below. If the partial pressures

Question

Consider the equilibrium system described by the chemical reaction below. If the partial pressures at equilibrium of NO, Cl₂, and NOCl are 0.095 atm, 0.171 atm, and 0.28 atm, respectively, in a reaction vessel of 7.00 L at 500 K, what is the value of Kp for this reaction?

2 NO(g) + Cl₂(g) ⇌ 2 NOCl(g)

Based on the given data, set up the expression for Kp and then evaluate it. Do not combine or simplify terms.

Kp= ---- =

Answer 1

2 NO(g) + Cl₂(g) ⇌ 2 NOCl(g)

0.095........0.171.......0.28.........@equilibrium

Kp = (NOCl)² / (NO)²(Cl₂) ... Kp expression

Kp = (0.28)² / (0.095)²(0.171)

Kp = 50.8