m<DEC = 1/2 (arc AB + arc CD)
m<AOB = 90 and is central angle so intercepted arc AB is equal to 90
m<COD = 16 and is central angle so intercepted arc CD is equal to 16
plugging values into equation:
m<DEC = 1/2 (90 + 16) = 53 (C)
Sarah L.
asked 02/24/21In the diagram, point O is the center of the circle and and
intersect at point E. If m∠AOB = 90° and
m∠COD = 16°, what is m∠CED?
A.
37°
B.
48°
C.
53°
D.
62°
m<DEC = 1/2 (arc AB + arc CD)
m<AOB = 90 and is central angle so intercepted arc AB is equal to 90
m<COD = 16 and is central angle so intercepted arc CD is equal to 16
plugging values into equation:
m<DEC = 1/2 (90 + 16) = 53 (C)
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