Arc AB = 360-250 = 110
m(Inscribed angle) = 1/2 measure of intercepted arc. <BDA intercepts arc AB, so m<BDA = 1/2 * 110 = 55
m(Exterior angle formed by two tangents) = 1/2 difference of measure of intercepted arcs.
m<BCA = 1/2 (250 - 110) = 70
Sarah L.
asked 02/24/21In this figure, m∠BDA = ___° and m∠BCA = ___°.
Arc AB = 360-250 = 110
m(Inscribed angle) = 1/2 measure of intercepted arc. <BDA intercepts arc AB, so m<BDA = 1/2 * 110 = 55
m(Exterior angle formed by two tangents) = 1/2 difference of measure of intercepted arcs.
m<BCA = 1/2 (250 - 110) = 70
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.