J.R. S. answered 02/24/21
Ph.D. University Professor with 10+ years Tutoring Experience
2Al(s) + 3CuCl2(aq) ==> 2AlCl3(aq) + 3Cu(s)
Use dimensional analysis to solve for g Cu:
33.0 g Al x 1 mol Al/27.0 g x 3 mol Cu / 2 mol Al x 63.5 g Cu/mol Cu = 116 g Cu