
Yefim S. answered 02/23/21
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Math Tutor with Experience
s = ∫0π(x'2(t) + y'2(t))1/2dt = ∫0π(4sin2(t) + 4cos2(t))1/2dt = 2t0π = 2π
Answer is D
Cameron L.
asked 02/23/21What is the length of the curve with parametric equations x = 1 - 2cos(t), y = 2 - 2sin(t) from t = 0 to t = π?
A | 8 |
B | 4 |
C | 8π |
D | 2π |
Yefim S. answered 02/23/21
Math Tutor with Experience
s = ∫0π(x'2(t) + y'2(t))1/2dt = ∫0π(4sin2(t) + 4cos2(t))1/2dt = 2t0π = 2π
Answer is D
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