Graham's Law of Effusion/Diffusion:
rate of gas 1 / rate of gas 2 = sqrt MW gas 2 / sqrt MW gas 1
rate CH4/rate N2 = sqrt MW N2 / sqrt MW CH4
340 / x = √ 28/16
340 / x = 1.32
x = 258 m/s = speed of diffusion of N2
Mar A.
asked 7dIf a molecule of CH4 diffuses a speed of 340 m/s from a point source, calculate the speed that a molecule of N2 would diffuse under the same conditions for the same period of time.
Graham's Law of Effusion/Diffusion:
rate of gas 1 / rate of gas 2 = sqrt MW gas 2 / sqrt MW gas 1
rate CH4/rate N2 = sqrt MW N2 / sqrt MW CH4
340 / x = √ 28/16
340 / x = 1.32
x = 258 m/s = speed of diffusion of N2
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