Step 1: Factor out the common factor (x^{4/3})^{ }of the equation [One way to think of it is to take out the common factor or multiply the equation by 1 or divide the equation by the factor]

(x^{4/3 }/ x^{4/3})(x^{10/3 }- 9x^{4/3}) = x^{4/3 }(x^{10/3}/^{ }x^{4/3}- 9x^{4/3}/x^{4/3}) = x^{4/3 }(x^{(10-4)/3}- 9x^{(4-4)/3}) = x^{4/3 }(x^{2}-9)

Ans: x^{4/3 }(x^{2}-9)

Step 2: Completely factor the expression [Notice there is another expression that can be factored down, which is also called a difference of two perfect squares]

To solve the difference of two perfect squares which in this case is x^{2} and 9, just split them and assign a positive and negative. To check, you can multiply it out and check that (a+b)(a-b) = a^{2}-b^{2}.

x^{4/3 }(x^{2}-9) = x^{4/3 }(x+3)(x-3)

Ans: x^{4/3 }(x+3)(x-3)