need chem answer

Question

A 5.4 L solution of potassium nitrate is diluted from its original concentration of 4.8 M to a new concentration of 0.78 M. What is the resulting volume of the diluted solution in liters.

Answer 1

Use C1V1 = C2V2

C1 = initial concentration = 4.8 M

V1 = initial volume = 5.4 L

C2 = final concentration = 0.78 M

V2 = final volume = ?

Solving or V2, we have...

V2 = C1V1 / C2

V2 = (4.8 M)(5.4 L) / (0.78 M)

V2 = 33.2 L = 33 L (2 sig.figs.)