If we were to plot this vector on a graph, we'd see that it's going 1 units in the x direction and 1 units in the y direction (up 1, over 1). This makes an isosceles right triangle, whose hypotenuse is the vector itself.
In the isosceles right triangle, we know that one of the angles is 90o. Then the other two angles have to be 45o and 45o.
Now we can look at the relationship of the hypotenuse/vector to the x-axis. It's sticking up at a 45o angle. In radians, that's π/4 ! Thus we can say that the direction of the vector is π/4.