
Yefim S. answered 02/22/21
Math Tutor with Experience
Distance traveled by particle d = ∫0π√(x'2 + y'2)dt = ∫0π √(4t)2+ (-sin(t))2dt = ∫0π(16t2 + sin2t)1/2dt = 19.89;
We used TI-84 to evaluate this integral
Cameron L.
asked 02/22/21The components of a position vector of a particle moving in the plane are . What is the distance traveled by the particle from t = 0 to t = π?
Type your answer in the space below and give 3 decimal places. If your answer is less than 1, place a leading "0" before the decimal point (ex: 0.482)
Yefim S. answered 02/22/21
Math Tutor with Experience
Distance traveled by particle d = ∫0π√(x'2 + y'2)dt = ∫0π √(4t)2+ (-sin(t))2dt = ∫0π(16t2 + sin2t)1/2dt = 19.89;
We used TI-84 to evaluate this integral
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