J.R. S. answered 02/20/21
Ph.D. University Professor with 10+ years Tutoring Experience
This question is asking you to find the temperature at which the rate constant (k) = 4.20x10-3s-1
The Arrhenius equation can be used to find this value...
ln (k2/k1) = - Ea/R (1/T2 - 1/T1)
k1 = 3.62x10-4 s-1
k2 = 4.20x10-3 s-1
Ea = 179 kJ/mol = 179,000 J/mol (note to change units to match those of R)
R = 8.314 J/Kmol
T1 = 577K
T2 = ?
ln (4.20x10-3 / 3.62x10-4) = -179000/8.314 (1/T2 - 1/577)
2.45 = -21530(1/T2 - 0.00173)
2.45 = -21530/T2 + 37.31
-34.86 = -21530/T2
T2 = 618K