John mixed 10ml of water at 60c with 50ml of water at 30c after stirring the water to mix it what was the temperature

Question

3rd grade chemistry 

Answer 1

For this problem, we will use the following equation:

T_final = (m₁*T₁ + m₂*T₂) / (m₁ + m₂)

As this equation requires the use of the mass of water, we will use the density of water, 1g = 1 mL.

m₁ = 10mL(1g/1mL) = 10 g

m₂ = 50ml(1g/1mL) = 50 g

After this, the problem becomes a "plug-and-chug" problem:

T_final = (10 g * 60°C + 50 g * 30°C)/ 10 g + 50 g = 35 °C

The final temperature is 35 °C.