
Yefim S. answered 02/18/21
Tutor
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Math Tutor with Experience
tan(t) = x/2; sec(t) = y/5; sec2(t) - tan2(t) = 1. From here we have y2/25 - x2/4 = 1
Answer is B: hyperbola y2/25 - x2/4 = 1
Cameron L.
asked 02/18/21Which of the following is the Cartesian equation for the parametric equation x = 2tan(t), y = 5sec(t)?
A | y = x2 - 9, for x in [-3,3] |
B | ![]() |
C | ![]() |
D | ![]() |
Yefim S. answered 02/18/21
Math Tutor with Experience
tan(t) = x/2; sec(t) = y/5; sec2(t) - tan2(t) = 1. From here we have y2/25 - x2/4 = 1
Answer is B: hyperbola y2/25 - x2/4 = 1
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