A solution is made initially with 0.200 M HIO₃ (Kc = 0.170). Once the equilibrium below is established, what is the equilibrium concentration of H⁺ ions? HIO₃ (aq) ⇌ H+ (aq) + IO₃⁻ (aq)

Question

A solution is made initially with 0.200 M HIO₃ (Kc = 0.170). Once the equilibrium below is established, what is the equilibrium concentration of H⁺ ions? HIO₃ (aq) ⇌ H+ (aq) + IO₃⁻ (aq)

Answer 1

Kc = [H⁺][IO3^-] / [HIO₃]

0.170 = (x)(x) / 0.200 - x

x² = 0.034 - 0.17x

x² + 0.17x - 0.034 = 0

x = 0.118 M = [H⁺]