J.R. S. answered 02/17/21
Ph.D. University Professor with 10+ years Tutoring Experience
Colligative Properties
∆T = imK
∆T = change in temperature
i = van't Hoff factor
m = molality = moles solute / kg solvent
K = 1.86º/m
LiCl molar mass = 42.4 g/mol
moles LiCl = 4.00 g x 1 mol / 42.4 g = 0.0943 moles
kg solvent = 1
m = 0.0943 mol/1 kg = 0.0943 m
∆T = 0.328º
Solving for i, we have...
i = ∆T / (m)(K) = 0.328 / (0.0943)(1.86)
i = 1.87 (theoretical value would be 2)
Do the HCl and NaCl in the same manner as was done for LiCl

J.R. S.
02/17/21
Kirsten H.
it says “The correct values for the van’t Hoff factors will be non-integer values less than the theoretical factor.” I do not know what that means. Can you help me to better understand it?02/17/21