Calculate the amount if heat required to heat 65 kg sample of ethanol from 11 degrees Celsius to 19 degrees Celcius

Answer 1

q = mC∆T

q = heat = ?

m = mass = 65 kg

C = specific heat of ethanol = 2.44 kJ/kgº (I looked it up on Wikipedia)

∆T = change in temperature = 19º - 11º = 8º

Solve for q..

q = (65 kg)(2.44 kJ/kgº)(8ª) = 1269 kJ = 1300 kJ (3 sig. figs.)