
Sam Z. answered 02/18/21
Math/Science Tutor
γ=acos((a^2+b^2-c^2)/(2ab))
" ((144+324-225)/(2*12*18))
" ((243) /432))
" .5625
γ=55.77°
a/sinα=b/sinβ=c/sinγ
122/sinα=15/.8267=18.142;
122/18.142=6.724°=α
γ=117.5054..........
Abhi P.
asked 02/17/21Solve ΔABC. (Round your answers to the nearest degree. If there is no solution, enter NO SOLUTION.)
a = 12, b = 18, c = 15
𝛼 = | ° |
𝛽 = | ° |
𝛾 = | ° |
Sam Z. answered 02/18/21
Math/Science Tutor
γ=acos((a^2+b^2-c^2)/(2ab))
" ((144+324-225)/(2*12*18))
" ((243) /432))
" .5625
γ=55.77°
a/sinα=b/sinβ=c/sinγ
122/sinα=15/.8267=18.142;
122/18.142=6.724°=α
γ=117.5054..........
Use the law of cosines to get angle B.324=225+144-360 cos angle beta
The the law of sines will get you one of the other 2 angles.
The third angle will be obtained from remembering that the sum of the angles of a triangle is 10 degrees.
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