Mattia M.

asked • 02/17/21

A person owns three suits, ten ties, and ten shirts. How many ways can they select a traveling wardrobe of two suits, four ties and six shirts?

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Jon S. answered • 02/17/21

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C * C * C

3 2 10 4 10 6


where C = n!

n k -----

k! (n-k)!

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Mattia M.

so what is the answer? Because I got 132300 and don't know if it is correct
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02/17/21

David B.

Yes, it is correct (that's assuming that all ties go with all suits and all shirts or that one is colour blind). You have 3C2 combinations of suits (order does not matter), 10C4 combinations of ties, and 10C6 combination of shirts. that is 3 * 210 *210
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02/20/21

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