Jeff R.

asked • 02/16/21

Chapters 18-19 Summative Assessment

Question 4 


Previous studies have indicated that about 70% of the plants in Delaware are flowering plants, but a botanist in the region suspects the proportion might actually be greater than 70%. The botanist selected a random sample of plants from the region and conducted a test of H0 : p = 0.7 versus HA : p > 0.7 and found a p-value of 0.025. Which of the following is a correct interpretation of the p-value?

 a If it is not true that 70 percent of the plants in Delaware are flowering, 0.025 is the probability of obtaining a sample proportion as large as or larger than the one obtained by the botanist.
 b If it is not true that 70 percent of the plants in Delaware are flowering, 0.025 is the probability of obtaining a population proportion greater than 0.7.
 c If it is true that 70 percent of the plants in Delaware are flowering, 0.025 is the probability of obtaining a sample proportion as large as or larger than the one obtained by the botanist.
 d If it is true that 70 percent of the plants in Delaware are flowering, 0.025 is the probability of obtaining a population proportion greater than 0.7.
 e If it is true that 70 percent of the plants in Delaware are flowering, 0.025 is the probability of obtaining a sample proportion as small as or smaller than the one obtained by the botanist.

Question 5 

A 90% confidence interval is found to estimate the proportion of residents in Kent County, Delaware who plan to vote in an upcoming election. Initially, a sample of 4,000 residents was used. What would be the relationship between the width of the original confidnece interval and the width of a new 90% confidence interval that used a sample of 1,000 residents?

 a The second confidence interval would be 4 times as wide as the original confidence interval.
 b The second confidence interval would be 1/2 as wide as the original confidence interval.
 c The second confidence interval would be 2 times as wide as the original confidence interval.
 d The second confidence interval would be 1/4 as wide as the original confidence interval.
 e The width of the second confidence interval would be equal to the width of the original confidence interval.


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