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Question

Determine the boiling point elevation is a solution of 124.0 mg of carvone (a.k.a oil of spearmint, C₁₀H₁₄O) dissolved in 1.44 g of carbon disulfide (K_b= 2.34°C/m).

I have tried to work this so many times but cannot seem to work it correctly enough to get the answer right. Any help would be greatly appreciated.

Answer 1

Colligative Properties:

Boiling Point Elevation...

∆T = imK

∆T = change in boiling point = ?

i = van't Hoff factor = 1 for the organic compound C10H14O

molar mass C10H14O = 150 g/mol

m = molality = moles/kg = 124.0 mg x 1 g/1000 mg x 1 mol/150 g = 8.27x10^-4 mol / 0.00144 kg = 0.574 m

K = boiling point constant = 2.34ºC/m

Solving for ∆T...

∆T = (1)(0.574)(2.34)

∆T = 1.34ºC