Dayv O. answered 02/15/21
Caring Super Enthusiastic Knowledgeable Geometry Tutor
x is 4, the hypotenuse (r, radius in circle) is √41, So y= √((√41)2-42)=5
tan(angle)=y/x=5/4
Elizabeth J.
asked 02/15/21
Dayv O. answered 02/15/21
Caring Super Enthusiastic Knowledgeable Geometry Tutor
x is 4, the hypotenuse (r, radius in circle) is √41, So y= √((√41)2-42)=5
tan(angle)=y/x=5/4
Yefim S. answered 02/15/21
Math Tutor with Experience
tanθ = sinθ/cosθ; sinθ = ±√(1 - 16/41) = ±5/(±√41); tanθ = ±5/4.
We can't make chose for sign: if θ in quadrant I, then tanθ = 5/4; if θ in quadrant IV then tanθ = -5/4
Yuri O. answered 02/15/21
16 years online, 464 former SAT problems drilled down
θ = arccos(4/√41) ≅ 51.34°
tan(51.34°) ≅ 1.24999
sin(theta)^2 + cos(theta)^2 = 1
so sin(theta)^2 + 16/41 = 1
sin(theta)^2 = 25/41
sin(theta) = 5/sqrt(41)
tan(theta) = sin(theta)/cos(theta) = 5/4
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Dayv O.
I agree with Yefim, the y coordinate can also be -5,;;;;;; (-5)^2+4^2=41 as well as 5^2+4^2=41, so tan (angle) for this problem would be one of two answers, 5/4 and -5/402/15/21