At what pressure would 0.150 mole of nitrogen gas at -23.0 o C occupy 8.90 L?

Question

If you can, please explain the steps.

Answer 1

Ideal Gas Law: PV = nRT

P = pressure = ?

V = volume = 8.90 L

n = moles = 0.150

R = gas constant = 0.08206 Latm/Kmol

T = temperature in K = -23ºC + 273 = 250K

Solving for P...

P = nRT/V = (0.150)(0.08206)(250) / (8.90)

P = 0.346 atm