Christina G.
asked • 02/15/21if angle CDf=(3x+14)°, angle FDE=(5x-2)°, and angle CDE =(10x-18)°, find each measure
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1 Expert Answer
By angle addition rule m<CDF + m<FDE = m<CDE
substituting the expressions given for the measures of those angles:
3x + 14 + 5x - 2 = 10x - 18
8x + 12 = 10x - 18
30 = 2x
x = 15
m<CDF = 3x + 14 = 3(15) + 14 = 59
m<FDE = 5x - 2 = 5(15) - 2 = 73
m<CDE = 10x - 18 = 10(15) - 18 = 132
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Mark M.
In what kind of figure are these angles located?02/15/21