How long will it take for the concentration of A to decrease from 0.850 M to 0.327 for the reaction A → Products? (k = 0.0882 M⁻¹s⁻¹)

Answer 1

Because the value of k has units of M^-1s^-1, we know that the reaction is second order.

For a second order reaction, the integrated rate law is 1/[A] = 1/[A]_o + kt

Substituting the known values and solving for t, we have...

1/0.327 = 1/0.850 + 0.0882 t

3.06 = 1.18 + 0.0882 t

t = 1.88 / 0.0882

t = 21.3 s