J.R. S. answered • 02/12/21
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1/2 Cr2O7-2 ==> Cr3+ ... balanced for Cr
1/2 Cr2O7-2 ==> Cr3+ + 7/2 H2O ... balanced for Cr and O
1/2 Cr2O7-2 + 7H+ ==> Cr3+ + 7/2 H2O ... balanced for Cr, O and H
1/2 Cr2O7-2 + 7H+ + 3e- ==> Cr3+ + 7/2 H2O ... balanced for Cr, O, H and charge = balanced half reaction
J.R. S.
tutor
Well, I certainly guess you could look at it that way, but I simply used the 7/2 (3.5) to balance the oxygens since we had 1/2 of 7 oxygens on the left side in Cr2O7. If you find it easier to use H-OH, there's nothing wrong with that. I do that sometimes.
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02/13/21
Kasonja H.
Thank you for your response! With the 7/2 H2O, does the twos ( the one as the denominator and 2 in H2O) cancel each other out? Will it make it easier to rewrite water as H-OH?02/13/21