J.R. S. answered 02/12/21
Ph.D. University Professor with 10+ years Tutoring Experience
Look up the standard reduction potentials for the two half reactions.
Li+ + e- ==> Li Eº = -3.04 V (anode)
Mn2+ + 2e- ==> Mn Eº = -1.185 V (cathode)
Eºcell = -1.185 + 3.04 = 1.86 V
If you required 1.5 V, this cell would work for your purpose since it will supply 1.86 V