Gas Laws chemistry

Question

Container A holds 727 mL of an ideal gas at 2.70 atm.

Container B holds 169 mL of a different ideal gas at 4.10 atm

If the gases are allowed to mix together, what is the resulting pressure?

Answer 1

Final volume after mixing = 727 ml + 169 ml = 896 ml

Use P1V1 = P2V2 and solve for P2 = P1V1/V2

For A: P2 = (2.70 atm)(727 ml) / 896 ml = 2.19 atm

For B: P2 = (4.10 atm)(169 ml) / 896 ml = 0.773 atm

Total pressure = 2.19 atm + 0.773 atm = 2.96 atm