Let's start with a balanced equation.
2Al2S3 + 6F2 = 4AlF3 + 6S
The equation tells us that we need six moles of F2 for every two moles of Al2S3. That's a ratio of 6:2 or 3:1.
If we assume we have plenty of F2 and also have 0.2784 moles of Al2S3, then we will consume three times that amount of F2, which would be 0.8352 moles of F2.