J.R. S. answered 02/11/21
Ph.D. University Professor with 10+ years Tutoring Experience
We need to know the standard enthalpy of formation for the reactants and products in each case.
For H2 in both cases, the value is zero, but we need the values for the other species. Then, when you have those values, you simply take the products - reactants.
So, for the first one...
[∆Hf CO + ∆Hf H2O] - [∆Hf CO2] = ∆Hrxn