Skippy cycles 30km west and 24 km south from where he started. Find Skippy’s distance from his starting point. ALS, find Skippy’s bearing of his final destination from his starting point.

Answer 1

Let d = distance

d² = 30² + 24² = 900 + 576 =1476

d = √1476 = 34.41 Km

Bearing:

tan(θ) = 24/30 = .8

θ = tan^-1(.8) = 38.66° 90-38.66 = 51.34

Bearing = S51.34°W

Answer 2

30^2 + 24^2 = 900+576 = 1476

sqr1476 = 38.42 km

the distance is the hypotenuse of a right triangle

hypotenuse squared = sum of squares of the two sides, 30 and 24

angle formed has tangent = 24/30 = 12/15 = 4/5 angle is 38.65 degrees SW