An empty 2 Liter flask is filled with: 1.705 atm of CO(g), 0.900 atm of COBr2(g), and 1.895 atm of Br2(g), at 260°C and allowed to reach equilibrium according to the reaction:

Question

COBr₂(g)    ⇄   CO(g) + Br₂(g)            K_p = 0.289 at 260°C

 

Calculate the value of Kc at 260°C

Answer 1

Kp = Kc(RT)^∆n

∆n = change in number of moles = 2 - 1 = 1

Kp = Kc(RT)¹

0.289 = Kc(RT)

Kc = 0.289 / (RT) = 0.289 / (0.0821*533K)

Kc = 6.60x10^-3