Percent Yield Chemistry Question

Question

If 220 grams of Ca(OH)2 are used in this reaction and produced 297.5 grams (actual yield) of CaCl2, what would the % yield be?

P.S

 You will need this The molar mass of Ca(OH)2 is 74 g/mol CaCl2 Is 110g /mol

Answer 1

What is the reaction? Is it Ca(OH)₂ + 2HCl => CaCl₂ + 2H₂O? If so, then proceed as follows:

220 g Ca(OH)₂ x 1 mol/74 g x 1 mol CaCl₂ / mol Ca(OH)₂ x 110 g/mol = 327 g CaCl₂ theoretical yield

%yield = actual yield/theoretical yield (x100%) = 297.5 g / 327 g (x100%) = 90.97% = 91% (2 sig.figs.)