Write an equation of the line that passes through the point (6,2) and is perpendicular to the line y=3x+3

Answer 1

Hi Wendy R.

Given y = 3x + 3; which is already in Slope Intercept Form

y = mx + b

m = 3

b = 3

The perpendicular line would a slope, m, that is the inverse and opposite in sign to 3 or (-1/3)

The perpendicular line in Slope Intercept Form starts as follows

y = (-1/3)x + b

Given that this perpendicular passes through the coordinates (6,2), we can use these to solve for b

y = (-1/3)x + b

2 = (-1/3)6 + b

2 = -2 + b

Add 2 to both sides of the equation to solve for b

2 + 2 = b

4 = b

So the perpendicular line in Slope Intercept Form is

y = (-1/3)x + 4

You can plot both lines at Desmos.com to see that they are perpendicular and that the perpendicular line passes through (6,2) give it a try

I hope this helps

If you have any questions please send me a message