Solid Co(NH3)(OH)3 is placed in a sealed container and held at a constant temperature of 600.00°C where Kc = 32.0 for the following reaction:

Question

Calculate K_p for this reaction at 600.00°C. 

Answer 1

Co(NH₃)₆(OH)₃(s) <==> Co(OH)₃(s) + 6NH₃(g) NOTE 6 moles of gas on right, no moles gas on left !!

Kp = Kc(RT)^∆n where ∆n is the change in number of moles = 6 - 0 = 6

R = gas constant = 0.0821 Latm/Kmol

T = temp in K = 600.00 + 273.15 = 873.15K

Kp = 32.0 (0.0821*873.15K)⁶

Kp = 4.3x10¹²