The point P is on the unit circle. If the x-coordinate of P is sqrt(3)/2, and P is in the quadrant IV, find the y coordinate.

Answer 1

Looking at the unit circle wheel, it would be -1/2

OR

y² = h²-x² = 2²-(√3)² --> y = ±1 take -1 since quadrant 4

y-coordinate of P = y/h = -1/2