J.R. S. answered 02/08/21
Ph.D. University Professor with 10+ years Tutoring Experience
First, write the correctly balanced equation:
6HCl + 2Al ==> 2AlCl3 + 3H2 ... balanced equation
Recall that at STP, one mole of any ideal gas occupies 22.4 liters.
Convert g Al to moles Al:
67.3 g Al x 1 mol Al / 26.98 g = 2.494 moles Al
Since HCl is in excess, we can find moles H2 formed from 2.494 moles of Al:
2.494 moles Al x 3 moles H2 / 2 moles Al = 2.494 moles H2
Using 22.4 L/mol, we can now convert this to liters of H2:
2.494 moles H2 x 22.4 L/mole = 55.9 L (3 sig. figs.)