P(z > 1.6) = 1 - P(z < 1.6) = 1 - 0.9452 = 0.0548
P(z < 3) = 0.9987
P(-1.4 < z < 0.5) = P(z < 0.5) - P(z < -1.4) = 0.6915 - 0.0808 = 0.6107
P|(|z| > 0.6) = P(z > 0.6) + P(z < -0.6) = 2 * P(z < -0.6) = 2*0.2743 = 0.5486
Chris J.
asked 02/07/21Find the probabilities/area under the curve, for the standard normal curve (N(mean =0, sd=1)).
P(Z>1.6)
P(Z<3)
P(-1.4<Z<0.5)
P(|Z|>0.6)
P(z > 1.6) = 1 - P(z < 1.6) = 1 - 0.9452 = 0.0548
P(z < 3) = 0.9987
P(-1.4 < z < 0.5) = P(z < 0.5) - P(z < -1.4) = 0.6915 - 0.0808 = 0.6107
P|(|z| > 0.6) = P(z > 0.6) + P(z < -0.6) = 2 * P(z < -0.6) = 2*0.2743 = 0.5486
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