What is the specific heat of titanium in J/g°C if it takes 99.7 J to raise the temperature of a 34.7 g block by 5.20°C?

Answer 1

q = mC∆T

q = heat = 99.7 J

m = mass = 34.7 g

C = specific heat = ?

∆T = change in temperature = 5.20º

Solving for C, we have...

C = q / (m)∆T) = 99.7 J / (34.7 g)(5.20º)

C = 0.553 J/gº