What is the molality of ions in a 0.479 m solution of SrCl₂ assuming the compound dissociates completely?

Question

What is the molality of ions in a 0.479 m solution of SrCl₂ assuming the compound dissociates completely?

Answer 1

Assuming that SrCl₂ dissociates completely, each mole of SrCl₂ will provide 3 moles of particles/ions.

SrCl₂ ==> Sr²⁺ + 2Cl^- (3 ions)

So, the molality of ions will be...

0.479 m x 3 = 1.44 m