2NO(g) + Br2(g) // 2NOBr(g)

Question

Consider the equilibrium system described by the chemical reaction below. For this reaction, Kp = 109 at 298 K. If the equilibrium partial pressures of Br₂ and NOBr at 0.0159 atm and 0.0768 atm, respectively, determine the partial pressure of NO at equilibrium..

(38)

Answer 1

2NO(g) + Br2(g) <==> 2NOBr(g)

................0.0159.............0.0768........Equilibrium partial pressures

Kp = (NOBr)² / (NO)²(Br₂)

109 = (0.0768)2 / (NO)²(0.0159)

109 = 0.005899 / 0.0159 x²

x = 0.00340

x = 0.0583 = partial pressure of NO