4Fe(s) + 3O2(g) // 2Fe2O3(s)

Question

Consider the equilibrium system described by the chemical reaction below. At equilibrium, a 2.0 L reaction vessel contained a mixture of 1.0 mol Fe, 1.0 × 10⁻³ mol O₂, and 2.0 mol of Fe₂O₃ at 2000 °C. What are the values of Kc and Kp for this reaction? (34)

Answer 1

4Fe(s) + 3O2(g) <==> 2Fe2O3(s)

[O2] = 1x10^-3 / 2 L = 5x10^-4 M

Kc = 1/(1)(5x10^-4)³ = 8x10⁹

Kp = Kc (RT)^∆n

Kp = 8x10⁹ (0.0821 * 2273)^-3

Kp = 1x10⁹ * 1.5x10^-7

Kp = 1.23x10³