Calculate the densities of both the water and the isopropyl alcohol and the percent error...

Question

The accepted value for the density of water is 1.00 g/mL and the accepted density for isopropyl alcohol is 0.786 g/mL.

percent error = experimental density minus accepted density divided by accepted density times 100

Mass A: graduated cylinder = 18.13 g

Volume of water put into the graduated cylinder = 5.0 mL

Mass B: graduated cylinder with liquid (water) = 22.96 g

Mass B - A: liquid (water) = 4.83 g

Density (g/mL) of water ?

Percent error of water ?

Mass A: graduated cylinder = 18.13 g

Volume of isopropyl alcohol put into the graduated cylinder = 5.0 mL

Mass B: graduated cylinder with liquid (isopropyl alcohol) = 22.21 g

Mass B - A: liquid (isopropyl alcohol) = 4.08 g

Density (g/mL) of isopropyl alcohol ?

Percent error of isopropyl alcohol ?

Answer 1

Hello Dawson. Happy to help.

The density is the relationship between the mass of an object and its volume.

so Density =mass of substance/volume of substance.

You measured the mass and volume of water and want to compare the experimental data to the known theoretical value.

First calculate your experimental density.

Density = mass of water 4.83g/volume of water 5.0mL

Density = 0.97g/mL

I am using 2 significant figures in the answer since 5.0 has 2 significant figures.

To calculate the percent error we use the following equation:

(Experimental-Theoretical)/Theoretical * 100

so you have (0.97-1.00)/1.00 *100

You will repeat the same steps for isopropyl alcohol.

I hope this helps. Please reach out to me if you have any additional questions.