J.R. S. answered 02/05/21
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q = mC∆T
q = heat = ?
m = mass = 610.0 g
C = specific heat = 0.3850 J/gº
∆T = change in temperatuer =25.85º - 14.99º = 10.86ºª
q = (610.0 g)(0.3850 J/gº)(10.86º)
q = 2550. J