AlCl₃ has a van't Hoff factor of i = 3.20. What is the concentration of particles in a 0.451 M solution of AlCl₃?

Question

AlCl₃ has a van't Hoff factor of i = 3.20. What is the concentration of particles in a 0.451 M solution of AlCl₃?

Answer 1

0.451 M AlCl3 = 0.451 moles AlCl3 / L

0.451 moles AlCl3 x 3.20 moles of particles / mole AlCl3 = 1.44 moles of particles

Concentration of particles = 1.44 M