A (g) ⇌ B (g) + C (g) (26)

Question

An empty steel vessel is charged with 0.240 atm of C and 0.240 atm of A. Once the system reaches equilibrium according to the reaction below, what is the equilibrium partial pressure of C? Kp for this reaction is 11.2.

Answer 1

A(g) <==> B(g) + C(g)

0.24.............0..........0.24.....I

-x..............+x...........+x........C

0.24-x.........x..........0.24+x...E

Kp = (B)(C) / (A)

11.2 = (0.24+x)(x) / 0.24-x

11.2 = x2 + 0.24x /0.24-x

2.69 - 11.2x = x2 + 0.24x

x2 + 11.4x - 2.69 = 0

x = 0.231

At Equilibrium, partial pressure of C = 0.231 atm