J.R. S. answered 02/05/21
Ph.D. University Professor with 10+ years Tutoring Experience
2 NO (g) + Cl₂ (g) ⇌ 2 NOCl (g)
.....................................3.60..........I
+2x.............+x............-2x..............C
..2x..............x...............0.16.........E
3.60 - 2x = 0.16
x = 1.72
Pressures at equilibrium:
NO = 2 x 1.72 = 3.44 atm
Cl2 = 1.72 atm
NOCl = 0.16 atm
Kp = (NOCl)2 / (NO)2(Cl2) = (0.16)2 / (3.44)2(1.72)
Kp = 1.26x10-3