
Yefim S. answered 02/04/21
Math Tutor with Experience
(A) sin13t + sin11t = 0; 2sin12tcost = 0;
sin12t = 0. 12t = πn, t = πn/12;
cost = 0, t = π/2 + πn
where n = 0,±1, ±2, ...
(B) cos6x + cos8x = cosx;
2cos7xcosx - cosx = 0; cosx(2cos7x - 1) = 0.
cosx = 0, x = π/2 + πn,
2cos7x - 1 = 0; cos7x = 1/2; 7x = π/3 + 2πn or 7x = 5π/3 + 2πn
x = π/21 + 2πn/7 or x = 5π/21 + 2πn/7
n = 0,±1, ±2, ...