Calculate the heat required to melt 25.7 grams of solid water at 0 ºC.

Answer 1

q = m∆Hfusion

q = heat = ?

m = mass = 25.7 g

∆H_fusion = 80 cal/g

q = (25.7 g)(80 cal/g) = 2056 cal

This is the heat in calories needed to melt 25.7 g of ice at 0ºC

If you want the answer in joules, then..

2056 cal x 4.184 J/cal = 8602 J

(NOTE: the latent heat of vaporization is not needed to answer this question)

Answer 2

q=mΔH_fus

q=(25.7g)(334^J/_g)

q=8583.8 J

q=8580 J