Yuri O. answered 02/04/21
16 years online, 464 former SAT problems drilled down
Equation for AB line:
-7x + 3y = -21.5
Solve for "y":
y = (7/3)x - (21.5)/3 → Slope-Intercept form
m = 7/3 → slope of line AB
Line PQ is perpendicular to line AB. It has point P: (7, 6)
mPQ = -1/m = -3/7 → slope of a line perpendicular to another line with a known slope
Write equation for PQ:
(y - 6) = (-3/7)(x - 7) → multiply by "-7"
-3x -7y = -63
Divided by "2":
-1.5x -3.5y = -31.5
Answer: B