
Yuri O. answered 02/03/21
16 years online, 464 former SAT problems drilled down
Red marbles: 20
Blue marbles: 32
Total number of red and blue marbles is 52
Pairs of two in 52:
52/2 = 26 (one can withdraw two marbles - without replacement - 26 times).
Pairs of two in 20:
20/2 = 10 (one can withdraw two red marbles - without replacement - 10 times)
26 - total number of cases to withdraw two marbles (of any combination of colors)
10 - number of desired cases (to withdraw two reds)
10/26 = 5/13 ≅ 0.38 → probability to withdraw two reds at once (without replacement)